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[Luchsen]

But e has no determined direction.

[Mighty Midget]

Perhaps _r.u.s.s. is onto something. Like he says, the lengths AB, AC or AD doesn't change the angles I'm after, but once you fix one length, the others are set, even though they are still unknown.

[_r.u.s.s.]

luchsen it has, because there is only one possible way to place the line so the BC and DC are equal

[GTX2GvO]

For starter this is how I look @ trigonometry:



Therefor your problem will look like the following in my opinion:



Now you end up wit 3 triangles.. (yes 3)

Namely: ABC ; ACD & ABD

To solve your issue I NEED (besides the known 3 angles @ A)
Either 2 sides OR 1 additional angle AND 1 side.

Or else there can't be a solution.

[Mighty Midget]

Let's see:

sin BAC / sin CAD = sin ABC / sin ADC

BAC and CAD are known and ABC + ADC = 180 - BAD
At least there is a relationship here.

EDIT: By giving AC a value, you get one side that two triangles share.

[GTX2GvO]

Originally Posted by Mighty Midget

By giving AC a value, you get one side that two triangles share.

Hmmm... That gives me line c.

That means I STILL need 1 of the following:
gamma(bottom), e1, e2, zèta(top)

Cause to solve this I need to start with. (from the perspective of 1 triangle)
2 sides and 1 angle OR
2 angles and 1 side.

We had 1 angle ( alfa, beta & alfa+beta )
And now we got 1 side ( c )

So I still need either one more side OR one more angle.

[_r.u.s.s.]

i think you are looking a bit narrowish on the problem gtx

[Kugerfang]

Invalid Syntax Error.

[Luchsen]

Originally Posted by _r.u.s.s.

luchsen it has, because there is only one possible way to place the line so the BC and DC are equal

Have fun fiddling around with that! My math teacher always yelled at me: "You are supposed to think and calculate, and not to insert values randomly!" Indignant me: "I don't do it randomly!"

[dosraider]

E.T. would know the answer .... E.T. would .....